A titration is performed using by adding 0.100 M NaOH to 40.0 mL of 0.1 M HCl.

c) Calculate the volume of base needed to reach the equivalence point.

Answer:

The equivalence point is the point in the titration where;

moles of base (NaOH) = moles of acid (HCl)

Since we are adding the base to the acid, we know how many moles of acid are present;

We need the same number of moles of base (NaOH) at the equivalence point;

0.00400 moles NaOH

Knowing the concentration of the NaOH we can use the moles of NaOH required to reach the equivalence point to determine the volume;

So 0.0400 L or 40.0 mLs of 0.100 M NaOH are required to reach the equivalence point in this titration.

We can see this point on the titration curve (as point 1c).

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